Happy Wednesday math friends! Today, we’re going to go over how to solve absolute value equations. Solving for absolute value equations supplies us with the magic of two potential answers since absolute value is measured by the distance from zero. And if this sounds confusing, fear not, because everything is explained below!

Also, if you have any questions about anything here, don’t hesitate to comment. Happy calculating! 🙂

Absolute Value measures the “absolute value” or absolute distance from zero. For example, the absolute value of 4 is 4 and the absolute value of -4 is also 4. Take a look at the number line below for a clearer picture:

Now let’s see how we can apply our knowledge of absolute value equations when there is a missing variable!

Now let’s look at a slightly different example:

Practice Questions: Given the following right triangles, find the missing lengths and side angles rounding to the nearest whole number.

Solutions:

Still got questions? No problem! Check out the video the same examples outlined above. Happy calculating! 🙂

Welcome back to Mathsux! This week, we’re going to go over how to find missing angles and side lengths of right triangles by using trigonometric ratios (sine, cosine, and tangent) (aka how to use SOH CAH TOA). Woo hoo! These are the basics of right triangle trigonometry, and provides the base for mastering so many more interesting things in trigonometry! So, let’s get to it!

Also, if you have any questions about anything here, don’t hesitate to comment below or watch the video below. Also, don;r forget to subscribe to Math Sux for FREE math videos, lessons, and practice questions every week. Happy calculating! 🙂

How to use SOH CAH TOA?

Trigonometric Ratios(more commonly known as Sine, Cosine, and Tangent) are ratios that naturally exist within a right triangle. This means that the sides and angles of a right triangle are in proportion within itself. It also means that if we are missing a side or an angle, based on what we’re given, we can probably find it!

Let’s take a look at what Sine, Cosine, and Tangent are all about!

Now let’s see how we can apply trig ratios when there is a missing side or angle in a right triangle!

Now for another type of question; using trig functions to find missing angles, let’s take a look:

Try the following Practice Questions on your own!

Solutions:

Still got questions? No problem! Check out the video the same examples outlined above and happy calculating! 🙂

Welcome to Mathsux! Today, we’re going to go over how to solve log equations, yay! But before we get into finding x, though, we need to go over what log equations are and why we use them in the first place…..just in case you were curious!

Also, if you have any questions about anything here, don’t hesitate to comment below or shoot me an email. Happy calculating! 🙂

What are Log Equations?

Logarithms are the inverses of exponential functions. This means that when graphed, they are symmetrical along the line y=x. Check it out below!

When on the same set of axis, notice how the functions are symmetrical over the line y=x:

We use logarithms to find the unknown values of exponents, such as the x value in the equation, . This is a simple example, where we know the value of x is equal to 2,(). But what if it were to get more complicated? That’s where logs come in!

How to Solve Log Equations?

Logarithms follow a swooping pattern that allows us to write it in exponential form, let’s take a look at some Examples below:

But wait there’s more! Logs have a set of Rules that makes solving log equations a breeze!

We can use these rules to help us algebraically solve logarithmic equations, let’s look at an example that applies the Product Rule.

Example:

Try the following practice questions on your own!

Practice Questions:

Solutions:

Still got questions? No problem! Check out the video that goes over the same example outlined above. And for more info. on logarithms check out this post that goes over a NYS Regent’s question here. Subscribe below to get the latest FREE math videos, lessons, and practice questions from MathSux. Thanks for stopping by and happy calculating! 🙂

Hi everyone, welcome back to Mathsux! This week we’ll be reviewing how to graph an equation of a line in y=mx+b form. And if you have not checked out the video below, please do! Happy calculating! 🙂

An equation of a line can be represented by the following formula:

y=mx+b

Y-Intercept: This is represented by b, the stand-alone number in y=mx+b. This represents where the line hits the y-axis. This is always the first point you want to start with when graphing at coordinate point (0,b).

Slope:This is represented by m, the number next to x in y=mx+b. Slope tells us how much we go up or down the y-axis and left or right on the x- axis in fraction form:

Now let’s check out an Example!

Graph the following:

-> First, let’s identify the slope and y-intercept of our line.

-> To start, let’s graph the first point on our graph, the y-intercept at point (0,1):

-> Now for the slope. We are going to go up one and over to the right one for each point, since our slope is 1/1.

-> Connect all of our coordinate points and label our graph.

Try the following practice questions on your own!

Practice Questions:

Want more Mathsux? Don’t forget to check out our Youtube channel and more below! And if you have any questions, please don’t hesitate to comment below. Happy Calculating! 🙂

Need to brush up on slope? Click here to see how to find the rate of change.

Happy Wednesday math friends! Today we’re going to go over the difference between perpendicular and parallel lines, then we’ll use our knowledge of the equation of a line (y=mx+b) to see how to find perpendicular and parallel lines through a given point. This is a common question that comes up on the NYS Geometry Regents and is something we should prepare for, so let’s go!

If you need any further explanation, don’t hesitate to check out the Youtube video below that goes into detail on how to find perpendicular and parallel lines through a given point one step at a time. Happy calculating! 🙂

Perpendicular Lines:

Perpendicular Lines: Lines that intersect to create a 90-degree angle and can look something like the graph below. Their slopes are negative reciprocals of each other which means they are flipped and negated. See below for example!

Example: Find an equation of a line that passes through the point (1,3) and is perpendicular to line y=2x+1 .

Parallel Lines:

Parallel lines are lines that go in the same direction and have the same slope (but have different y-intercepts). Check out the example below!

Example: Find an equation of a line that goes through the point (-5,1) and is parallel to line y=4x+2.

Try the following practice questions on your own!

Practice Questions:

1) Find an equation of a line that passes through the point (2,5) and is perpendicular to line y=2x+1.

2) Find an equation of a line that goes through the point (-2,4) and is perpendicular to line

3) Find an equation of a line that goes through the point (1,6) and is parallel to line y=3x+2.

4) Find an equation of a line that goes through the point (-2,-2) and is parallel to line y=2x+1.

Solutions:

Need more of an explanation? Check out the video that goes over these types of questions up on Youtube (video at top of post) and let me know if you have still any questions.

Greeting math peeps and welcome to MathSux! In this post, we are going to go over 4 ways to Factor Trinomials and get the same answer, including, (1) Quadratic Formula (2) Product/Sum, (3) Completing the Square, and (4) Graphing on a Calculator. If you’re looking for more don’t forget to check out the video and practice questions below. Happy Calculating! 🙂

Choose the factoring method that works best for you and try the practice problems on your own below!

Practice Questions:

Solutions:

Want a review of all the different factoring methods out there? Check out the ones left out here (DOTS and GCF) and happy calculating! 🙂

For even more ways to factor quadratic equations, check out How to factor by Grouping here! 🙂

Also, if you want more Mathsux? Don’t forget to check out our Youtube channel and more below! If you have any questions, please don’t hesitate to comment below. Happy Calculating! 🙂

Hi everyone and welcome to Math Sux! In this post, we are going to look at how to use and applythe median of a trapezoid theorem. Thankfully, it is not a scary formula, and one we can easily master with a dose of algebra. The only hard part remaining, is remembering this thing! Take a look below to see a step by step tutorial on how to use the median of a trapezoid theorem and check out the practice questions at the end of this post to truly master the topic. Happy calculating! 🙂

*If you haven’t done so, check out the video that goes over this exact problem, also please don’t forget to subscribe!

Step 1: Let’s apply the Median of a Trapezoid Theorem to this question! A little rusty? No problem, check out the Theorem below.

Median of a Trapezoid Theorem: The median of a trapezoid is equal to the sum of both bases.Step 2: Now that we found the value of x , we can plug it back into the equation for median, to find the value of median

Want more practice? Your wish is my command! Check out the practice problems below:

Practice Questions:

1.is the median of trapezoid ABCDEF, find the value of the median, given the following:2. is the median of trapezoid ACTIVE, find the value of the median, given the following:3.is the median of trapezoid DRAGON, find the value of the median, given the following:

4. is the median of trapezoid MATRIX, find the value of the median, given the following:

Solutions:

Need more of an explanation? Check out the detailedvideoand practice problems. Happy calculating! 🙂

Want to learn the ins and out of completing the square? Then you’ve come to the right place! Learn how to Complete the Square step by step in the video and article below, then try the practice problems at the end of this post to truly master the topic! If you’re looking for more on completing the square, check out this post here. Happy Calculating! 🙂
Check out the video below for an in-depth look at completing the square:

To answer this question, there are several steps we must follow including:
Step 1: Move the whole number, which in this case is 16, to the other side of the equation.
Step 2: Make space for our new number on both sides of the equation. This number is going to be found by using a particular formula shown below:
Step 3: Add the number 9 to both sides of the equation, which we found using our formula.
Step 4: Combine like terms on the right side of the equation, adding 16+9 to get 25.
Step 5: Now, we need to re-write the left side of the equation using the following formula.
Step 6: Finally, we solve for x by taking the positive and negative square root to get the following answer and solve for two different equations:
Practice Questions:Solutions:

Want more Mathsux? Don’t forget to check out our Youtube channel and more below! And if you have any questions, please don’t hesitate to comment below. Happy Calculating! 🙂

Need more of an explanation? Check out why we complete the square in the first place here ! 🙂

Hi math friends, has anyone been cooking more during quarantine? We all know there is more time for cookin’ and eatin’ cakes but have you ever been curious about the exact amount of cake you are actually eating?! Well, you’re in luck because today we are going to go over how to find the area of a piece of cake, otherwise known as the Area of a Sector!

Now, we’ll all be able to calculate just how much we are overdoing it on that pie! Hopefully, everyone is eating better than I am (I should really calm down on the cupcakes). Ok, now to our question:

*Also, If you haven’t done so, check out the video that goes over this exact problem, and don’t forget to subscribe!

Explanation:

How do I answer this question?

We must apply/adjust the formula for the area of a circle to find the area of the blue shaded region otherwise known as the sector of this circle.

How do we do this?

Before we begin let’s review the formula for the area of a circle. Just a quick reminder of what each piece of the formula represents:

Step 1: Now let’s fill in our formula, we know the radius is 5, so let’s fill that in below:

Step 2: Ok, great! But wait, this is for a sector; We need only a pieceof the circle, not the whole thing. In other words, we need a fraction of the circle. How can we represent the area of the shaded region as a fraction?

Well, we can use the given central angle value, , and place it over the whole value of the circle, . Then multiply that by the area of the entire circle. This will give us the value we are looking for!

Step 3:Multiply and solve!

Ready for more?Try solving these next few examples on your own to truly master area of a sector!

Practice Questions:

Find the area of each shaded region given the central angle and radius for each circle:

Solutions:

What do you think of finding the area of sector? Are you going to measure the area of your next slice of pizza? Do you have any recipes to recommend? Let me know in the comments and happy calculating! 🙂

Today we’re back with Algebra 2, this time solving for radical equations! Did you say “RadicalEquations?” As in wild and crazy equations? No, not exactly, radicals in math are used to take the square root, cubed root, or whatever root of a number.

Example #1:

Radicals are actually pretty cool because we can write them a couple of different ways and they all mean the same thing! Check it out below:Still not sure of their coolness? Let’s see what they look like with actual numbers: Example: Solve the following algebraic equation below for the missing variable (aka, solve for x).Explanation:

How do I answer this question?

The question wants us to solve for x using our knowledge of radicals and algebra. You can also check out how to solve this question on Youtube here!

How do we do this?

Step 1: We start solving this radical equation like any other algebraic problem: by getting x alone. We can do this easily by subtracting 7 and then dividing out 5.

Step 2: Now, to get rid of that pesky radical, we need to square the entire radical. Remember, whatever we do to one side of the equation, we must also do to the other side of the equation, therefore, we also square 14 on the other side of the equal sign. *This gets rid of our radical and allows us to solve for x algebraically as normal!

What happens when there is a cubed root though!?!?

When dividing polynomials with different value roots, raise the entire radical to that same power of root to cancel it out:Remember, we know radicals can also be written as fractions:

Therefore we also know that if we raise the entire radical expression to the same power of the root, the two exponents will cancel each other out:

Example #2:

Want more practice? Try solving radical equations in the next few examples on your own.

Practice:

Solutions:

Looking to brush up on how to solve absolute value equations? Check out the post here! Did I miss anything? Don’t let any questions go unchecked and let me know in the comments! Happy calculating! 🙂

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